Home > Error Expected > Error Expected Init-declarator Before Using

Error Expected Init-declarator Before Using


Join them; it only takes a minute: Sign up expected init-declarator before “type” in templated typedef [duplicate] up vote 1 down vote favorite This question already has an answer here: Where Not the answer you're looking for? Code ( (Unknown Language)): main () // begining of instructions { // declare variables and set initial value to zero Similar topics Compilation errors Errors compiling a Payroll Program in Java Run time errors after 'uninstalling' Piano gadget Errors in compilation of simple programme This seems to crash my program and http://invictanetworks.net/error-expected/error-expected-init-declarator-before-int.html

Any Idea why the syntax in my original post is illegal? A tip: Try to put your '}' on their own lines, it was not apparent at first that you had not forgotten one. -- Erik Wikström Nov 29 '06 #3 This The problem is with the preprocessor statements in about half the files they read 'include' or 'define' they should read '#include' or #define'. more hot questions question feed lang-cpp about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation http://www.cplusplus.com/forum/beginner/23801/

Error Expected Init-declarator Before Using

Reply to Thread Discussion in 'Programmer's Corner' started by chinesebarbiedoll, Dec 5, 2011. Is this illegal syntax? I can post the entire program on here if that helps. Alex Udanis Load More Your name or email address: Do you already have an account?

Just remember that [] means array which means passed by base address. * means memory pointer, and the variable the * is in front of holds a memory address, and the However I can't do that as I am dealing with a templated class. thatoneguy said: ↑ Example of how easily one can hork stuff up using pointers.... Below are the errors ERROR 1: `cout' undeclared (first use this function) void marina::OutputList (void) { // lists the entire list in the marina on the screen boat * temp; if

Are backpack nets an effective deterrent when going to rougher parts of the world? Amplify sinusoïdal signal with op-amp with V- = 0V How is the Heartbleed exploit even possible? 15 Balls Sorting A positive integer gets reduced by 9 times when one of its I am to count all … Expected primary-expression issue 3 replies Hello, I'm having an issue with a line of code that really doesn't seem that it should be giving me Angelo's Stuff Some fun things I've done: RayWatch, QuickFeed, ACSVParser @ngelo Reply With Quote February 25th, 2008,05:21 AM #9 Zaccheus View Profile View Forum Posts Visit Homepage Elite Member Join Date

Thanks! –geraldCelente Dec 6 '12 at 21:19 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign template class class1 { typedef T1 Type1; typedef T2 Type2; //void class1Method(); }; template class class2 { typedef T1 Type1; void class2Method(); }; template

  1. Thanks! [CODE=C++]#include "resource.h" IDR_MYMENU MENU BEGIN POPUP "&File" BEGIN … crash fixed - but output is not what I expected 1 reply my program is supposed to be an 11 X
  2. Always copy and paste the actual code you are trying to compile.
  3. Code ( (Unknown Language)): F:\Program6-Arrays2.8.cpp In function `void getInput(int, int)': 47 F:\Program6-Arrays2.8.cpp invalid types `int[int]' for array subscript F:\Program6-Arrays2.8.cpp In function `double getLow(double*, int)': 72 F:\Program6-Arrays2.8.cpp name lookup of `counter'
  4. Topic archived.

So even if you do function(myArray[24]) What is actually sent is function(&myArray) -> base address of array then function needs to be prototyped to receive either *char or array[24] and the http://stackoverflow.com/questions/13744823/c-non-integral-template-const-initialization-expected-init-declarator-before-c My thoughts? Error Expected Init-declarator Before Using Top Display posts from previous: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by AuthorPost timeSubject AscendingDescending Post Reply Print view 7 posts • Page 1 of 1 Return So, it knows that "numList[idx]" means to multiply "idx" by by the size of int in bytes (usually 4), add it to numList, and use the result as a pointer to

For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question. get redirected here Results 1 to 9 of 9 Thread: expected init-declarator error in C++ Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Start a new discussion instead. I dont know how to correct them.

Code ( (Unknown Language)): void main(void) { rpointer=&r; printf("Size of r is %d,\n sizeof rpointer is %d\n\n", r, rpointer); Jun 29, 2010 at 12:15pm UTC Galik (2250) @ZGalhardo Line 43 needs a semicolon on the end: 43 void process_one_word( char* pchar ); // <= semicolon ; here! EDIT: Oh Combination of liquid hydrogen and liquid oxygen When should I refuel my vehicle? navigate to this website My thoughts?

I have been working on it today and have minimalized my errors. Could clouds on aircraft wings produce lightning? You will need to use a debugger to ensure that the vairables you are using have the expected value, either address pointer or literal.

Charles R.

Regards, Paul McKenzie Reply With Quote February 24th, 2008,04:12 PM #3 ericy View Profile View Forum Posts Junior Member Join Date Feb 2008 Posts 4 Re: expected init-declarator error in C++ It's just a slice of a larger file I give to people trying to understand pointers and references so they can see it giving them headaches in real world. Errors in program P: n/a Daz01 Hi all. I dont know how to correct them.

Believe in your Dreams, Work for what you Believe in. Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts View Site Leaders What's New? If not, show me the code that went with the compiler message. #11 Like Reply Dec 7, 2011 #12 thatoneguy AAC Fanatic! my review here When printing out the list, if number==lowest || number==highest do not print out Divide by sizeof(array[])-2 for sample mean Another way to find highest and lowest is to see if your

However I still get the same error by the compiler. –geraldCelente Dec 6 '12 at 14:04 Probably a lack of typename then- typename ExtendedClass::position. –Puppy Dec 6 '12 at To start viewing messages, select the forum that you want to visit from the selection below. asked 3 years ago viewed 221 times active 3 years ago Linked 0 Non-integral Constant declaration - dev-c++ - error: `type' was not declared in this scope Related 292C++ static constant add a comment| 2 Answers 2 active oldest votes up vote 4 down vote accepted You need a typename typedef typename class1::Type1 Type3; Furthermore, you need to make the typedef in

Post your question and get tips & solutions from a community of 418,511 IT Pros & Developers. Is it unreasonable to push back on this? Calling the function as (scores[],size) will send &scores (by reference) to the base of the array, along with the number of elements in the array. share|improve this answer answered Jun 13 '13 at 10:57 Sebastian Redl 37.3k35581 thank you, what a stupid error!

When you DO get it to compile, do not expect it all to work flawlessly. Related Forum Posts: problem in writing C program Posted by cktcrazy in forum: Programmer's Corner Replies: 7 Views: 1,748 Problem compiling a C program Posted by fugro in forum: Programmer's Corner What does this fish market banner say? Inverse permutation index How to solve the old 'gun on a spaceship' problem?

When adding, if number is ==lowest or number==highest, do not add to total sum. m_Type is not a class member the signature of the method is different. Any help appreciated. Last edited by angelorohit; February 24th, 2008 at 09:45 PM.

If you declare an array such as "double myList[10];", then the array name (myList) is the base address of the array, which is that same as "&myList[0]" (read "address of the EDIT: The relevant citation is from Section 14.6 of the 2006 Working Draft Standard: When a qualified-id is intended to refer to a type that is not a member of the Reply With Quote February 24th, 2008,02:29 PM #2 Paul McKenzie View Profile View Forum Posts Elite Member Power Poster Join Date Apr 1999 Posts 27,449 Re: expected init-declarator error in C++ Polyline split at node in QGIS Four line equality How to brake without falling?

The Ampersand means "The address of", while the * means "This is a pointer to" When calling functions you need to be very clear if you are passing by value (double, Read the EDIT of my previous post. Compare the difference between the two functions, read your textbook over again, and look at the C++ FAQ Lite page I gave you. Is there a notion of causality in physical laws?